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Write a program to accept three Employee name and Basic salary. Print employee Net pay after calculation the following:

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рдПрдХ рдк्рд░ोрдЧ्рд░ाрдо рдмрдиाрдЗрдпे рдЬिрд╕рдоे рддीрди Employee рдХा рдиाрдо рдФрд░ рдмेрд╕िрдХ рд╕ैрд▓рд░ी рдЗрдирдкुрдЯ рдХрд░ें, рдиिрдЪे рджिрдП рдЧрдП рдХंрдбीрд╢рди рдХे рдЕрдиुрд╕ाрд░ Employee рдХा рдиेрдЯ рдкे рдк्рд░िंрдЯ рдХрд░ें

рдЗрд╕рдоें 3 condition рдпे рд╣ै:
  1. рдпрджि Employee рдХी рдмेрд╕िрдХ рд╕ैрд▓рд░ी 5000 рд╕े рдЬ्рдпाрджा рд╣ै рддो рдЙрд╕े HRA 1500 рджिрдпा рдЬाрдпे рдЕрди्рдпрдеा 800
  2. рдпрджि Employee рдХी рдмेрд╕िрдХ рд╕ैрд▓рд░ी 5000 рд╕े рдЬ्рдпाрджा рд╣ै рддो рдЙрд╕े Bonus 20% рджिрдпा рдЬाрдпे рдЕрди्рдпрдеा 10%
  3. рдпрджि Employee рдХी рдмेрд╕िрдХ рд╕ैрд▓рд░ी 5000 рд╕े рдЬ्рдпाрджा рд╣ै рддो рдЙрд╕े PF 15% рджिрдпा рдЬाрдпे рдЕрди्рдпрдеा 0

Write a program to accept three Employee name and Basic salary. Print employee Net pay after calculation the following:

  • HRA = 1500 if basic is >5000 else 800
  • BONUS = 20% of basic if Basic is >5000 else 10% of basic
  • PF = 15% of basic if basic is >5000 else 0
    screenshot

    Solve Using Python:




    Solve Using C:

    Select and press Ctrl+C

    #include 
    float calcnetpay(float basicsalery) {
        float hra, bonus, pf;
        if (basicsalery >= 5000) {
            hra = 1500;
            bonus = 20 * basicsalery/100;
            pf = 15 * basicsalery/100;
        } else {
            hra = 800;
            bonus = 10 * basicsalery / 100;
            pf = 0;
        }
        float net_pay = basicsalery + hra + bonus - pf;
        return net_pay;
    }
    int main() {
        char empname[3][50];
        float bsalery[3];
        for (int i = 0; i < 3; i++) {
            printf("Enter name of Employee %d: ", i+1);
            scanf("%s", empname[i]);
            printf("Enter basic salary of Employee %d: ", i+1);
            scanf("%f", &bsalery[i]);
        }
        for (int i = 0; i < 3; i++) {
            float net_pay = calcnetpay(bsalery[i]);
            printf("%s's net pay: %.2f\n", empname[i], net_pay);
        }
        return 0;
    }
    

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